However, searching for the character ‘u’ with a blank space following results in includes() returning false, as this combination of characters does not exist in const str. In the above example, searching for the character ‘u’ using includes() returns true, as the character exists in the string. This is why blank spaces count as part of the pattern to detect, and why it is possible to search for fractions of words – or even single characters, as seen below: console.log(str.includes('u')) The includes() method searches strings using character combination matches. Blank spaces are also taken into account when searching a String or an Array. Searching for “Includes” with a capital I will return false. Important: includes() is case sensitive!! As the value of const str contains the search string (included as the character combination i-n-c-l-u-d-e-s), the method returns true. In the example above, the includes() method is used to search the string variable const str for the word “ includes”.

The following example demonstrates basic usage of includes() when working with a String: const str = 'This String includes the word includes' This article introduces the basics of the includes() method for each prototype, as well as exploring the differences between the two. This method accepts a search value as a parameter, and returns true if the value is either contained in the array on which it is called, or if it exists as a substring of the string object on which it is called. The includes() method is part of both the Array and String prototypes.

Js array includes